Question

limxtendsto 1(x-1)/2x²+5x-7​

Answer 1

$\frac{1}{9}$

Step-by-step explanation:

$\lim_{x\rightarrow 1}\frac{x-1}{2x^{2} + 5x - 7}$

On putting the value of x, if we get $\frac{0}{0}$, $\frac{\infty}{\infty}$ then

We can use L-Hospital rule $\lim_{x\rightarrow 0}\frac{f(x)^{'}}{g(x)^{'}}$

$= \lim_{x\rightarrow 1}\frac{1}{2 \times 2x + 5}$

$= \frac{1}{2 \times 2 + 5}$

$= \frac{1}{9}$