Question

line 3x-4y=18 meets x axis at A and y axis at B.Find the area of triangle AOB where O is the origin

Answer 1

Here Triangle AOB is a right angled triangle

Because if you draw the graph of 3x-4y=18 then you will find that the graph will meet x axis at 6 and y axis at -9/2 and it's isa straight line.

so, Area= 1/2*6*9/2=27/2.

Answer 2

Area =c^2 /2|ab|=364/2|3*(-4)|=324/24=27/2
Where a=3,b=-4,c=-18