Question

Line A passes through points (6, 8) and (1, -7). Line B is perpendicular to Line A. Line Cis perpendicular to Line B. What is the slope of Line C?

Answer 1

Given Line B is perpendicular to Line A and Line C is perpendicular to Line B! So Line A is parallel to Line C!

So

Slope of Line A = Slope of Line C

$slope \: = (\: y2 - y1) \div( x2 - x1)$

So

Slope of Line C = (8 - (- 7))/(6 - 1) = 3!

Hope it helps!