Line AB and CD intersect at P. If angle APC = 2x+30° and angle BPD = 4x -20° then find x angle APC and angle BPD
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The value of x is 25 and ∠APC = ∠BPD = 80°
GIVEN
Line AB and CD intersect at P. If ∠APC = 2x+30° and ∠BPD = 4x -20°
TO FIND
- Value of x
- ∠APC
- ∠BPD
SOLUTION
We can simply solve the above problem as follows;
We are given,
A̅B̅ and C̅D̅ intersect at P
Therefore,
∠APC = ∠BPD (Vertically opposite angles of lines intersecting at a point are equal)
Therefore,
2x + 30 = 4x-20
Solving for x
30+20 = 4x-2x
50 = 2x
x = 50/2 = 25
Therefore,
The value of x = 25
∠APC = 2x + 30 = 2×25 + 30 = 80°
∠BPD = 4x -20 = 4×25 -20 = 80°
Hence, The value of x is 25 and ∠APC = ∠BPD = 80°
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