Question

Line AB is paralllel to line CD. PQ is transversal intersecting AB at O and CD at S. If angle AOP =63 degrees , find angle DSQ . *
1 point
63 degrees
97 degrees
117 degrees
127 degrees​

Answer 1

Answer:

Given

Angle AOP=63°

To find

Angle DSQ

Sol.

Angle AOP =Angle CSD= 63°...........corresponding angles are equal.

Angle CSD= Angle DSQ=63°..........Vertically opposite angle are equal.

Therefore, Angle DSQ=63°.

A

Answer 2

Answer:

63°

Step-by-step explanation:

<AOP+POB=180° (linear pair ) ,63° + POB =180°. POB=180-63 = 117°. <POB=<OSD =117° <OSD +<DSQ = 180° (linear pair). 117° + <DSQ=180(linear pair) ,<DSQ=180-117=63°