Question

Line AC and line BD intersed at point P m of angle APB=34°. Find m of angle APD and m of angle BPC

Answer 1

$\huge\bf{Answer}$

Given:-

•AC and BD intersect each other at point p

$\small\bf{m\:of\:∠ APB-34°}$

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Solution:-

$\large\bf{∠ APB + ∠ APD=180° }$

$\Rightarrow$$\tt{34°+ ∠APD=180°}$

$\Rightarrow$$\tt{∠ APD=180°- 34°}$

$\Rightarrow$$\tt{∠ APD=146°}$

$\Rightarrow$$\tt{∠ APD-∠ BPC}$

$\Rightarrow$$\tt{∠ BPC=146⁰}$

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Answer:-

•$\tt{∠ APD=146°}$

•$\tt{∠ BPC=146⁰}$