Question

line CD passes through points c (3 -5) and D(6,0) what is the equation of the line CD in standard form​

Answer 1

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$Coordinates \: of \: point \: C(3, -5) \: and \: D(6, 0) \\ </p><p>so \: x1 = 3, \: y1 = - 5, \: x2 = 6, \: y2 = 0 \\ </p><p></p><p>Equation \: of \: line \: CD \: using \: two \: point \: form \: is \\ \small\bold\red{y - y1 = \frac{y2 - y1}{x2 - x1}(x - x1) } \\ so \: y - ( - 5) = \frac{0 - ( - 5)}{6 - 3} (x - 3) \\ y + 5 = \frac{5}{3} (x - 3) \\ 3y + 15 = 5x - 15 \\ 5x - 3y - 30 = 0$