line from the origin.
If p and p' are the perpendicular distance from the origin upon the straight lines whose
= a and x cos 0 - y sin 0 -
equations are x sec 0 + y cosec o
a cos' o. prove that
4p? + (2p') = 4a? cos.
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Answer:
a²
Step-by-step explanation:
Given : Equations of lines
xsecθ+ycscθ=a⇒xsecθ+ycscθ−a=0 ...(1)
and xcosθ−ysinθ=acos2θ⇒xcosθ−ysinθ−acos2θ=0 ...(2)
We know that the coordinates of the origin (x1,y1)=(0,0).
We also know that the standard equation of the line is ax+by+c=0.
Comparing Eqs. (1) and (2) with the standard equation, we get
a1=secθ,b1=cscθ,c1=−a,a2=cosθ,b2=−sinθ and c2=−acos2θ
Therefore,the length of the perpendicular from the origin to the line (1) is given by
(p)=a2+b2∣ax1+by1+c1∣=sec2θ+csc2θ∣secθ×(0)+cscθ×(0)−a∣
= a²
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Answer:
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