Computer Science, asked by rachanabod20902, 3 months ago

line inclined at 40 to the vp has its ends 50mm and 20 mm above the hp.The length of its front view is 65 mm and its vt is 10 mm​

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Answered by rakhipatil021
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Answer:

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Answered by rahmanrahman25094
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Explanation:

Projection of lines(new)

1. Projection of straight line Line inclined to both HP & VPType-IGiven projections (FV & TV) of the line. To find True length & trueinclination of the line with HP (θ) and with VP(Φ). PROBLEM End A of a line AB is 15mm above HP & 20mm in front of VP while its end B is 50mm above HP and 75mm in front of VP. The distance between end projectors of the line is 50mm. Draw projections of the line and find its true length and true inclination with the principal planes. Also mark its traces.

2. b’ b1 ’ θ: True inclination of the line with HP = 24º TL 50 a’ b2’ α : Inclination of FV of θ α the line with HP/XY HT VT’ 15X Y v h’ 50 Ø: True inclination of 20 Φ β b1 the line with VP = 41º a β : Inclination of TV of 75 the line with VP/XY TL b b2

3. Line inclined to both HP & VPType –IIGiven (i) T.L., θ and Ø, (ii) T.L., F.V., T.V.to draw projections, find α, β,H.T. and V.T. PROBLEM A line AB, 70mm long, has its end A 15mm above HP and 20mm in front of VP. It is inclined at 30° to HP and 45°to VP. Draw its projections and mark its traces.

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