Math, asked by vedikasaini777, 1 month ago

Line / is the bisector of an angle A and B is any point on I. BP and BQ are perpendiculars from B to the arms of 2 A (see Fig. 7.20). Show that: (1) A APB = A AQB (1) BP =BQ or B is equidistant from the arms of ZA B А P р ​

Answers

Answered by alen033296
1

Answer:

( HOPE YOU UNDERSTOOD )

Step-by-step explanation:

In △APB and △AQB

∠APB=∠AQB (Each 90  

o

)

∠PAB=∠QAB (l is the angle bisector of ∠A)

AB=AB (Common)

∴△APB≅△AQB (By AAS congruence rule)

∴BP=BQ (By CPCT)

It can be said that B is equidistant from the arms of ∠A

Answered by shivay41
2

Answer:

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