Line / is the bisector of an angle A and B is any point on I. BP and BQ are perpendiculars from B to the arms of 2 A (see Fig. 7.20). Show that: (1) A APB = A AQB (1) BP =BQ or B is equidistant from the arms of ZA B А P р
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( HOPE YOU UNDERSTOOD )
Step-by-step explanation:
In △APB and △AQB
∠APB=∠AQB (Each 90
o
)
∠PAB=∠QAB (l is the angle bisector of ∠A)
AB=AB (Common)
∴△APB≅△AQB (By AAS congruence rule)
∴BP=BQ (By CPCT)
It can be said that B is equidistant from the arms of ∠A
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