Question

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form? 7x + 2y = –1 7x + 2y = 1 14x + 4y = –1 14x + 4y = 1

Answer 1

Answer:2y+7x=1

Step-by-step explanation:j(-3,11) k(1,-3)

Slope=m=11-(-3)/(-3)-1= -14/4=-2/7

Eqn of line: y=mx+c

y=(-7/2)x+c

Passes through (1,-3)

-3=(-7/2)+c

C=1/2

So the equation of line is y=(-7/2)x+1/2

Or 2y+7x=1

Answer 2

Answer:

the anwser is b

Step-by-step explanation:

:)