Question

Line l is bisector of an angle A and B is any point on l.BPand BQ are perpendicular from B to the of angle A​

Answer 1

Answer:

here you go -

Explanation:

In △APB and △AQB

∠APB=∠AQB (Each 90

o

)

∠PAB=∠QAB (l is the angle bisector of ∠A)

AB=AB (Common)

∴△APB≅△AQB (By AAS congruence rule)

∴BP=BQ (By CPCT)

It can be said that B is equidistant from the arms of ∠A.