Question

Line l is perpendicular to x+3y-3=0 and it passes through 1,7

Answer 1

Answer: x- 3y = 3

⇒(-x/3) + 1 = y [∵y=mx+c]

∴m of given line=(-1/3)

M of required line= -1/(-1/3)= 3

By slope point form,

y-y₁= m [ x- x₁]

y-7= (3)[x-1]

y-7=3x-3

∴ Equation of the line 3x-y+4=0

P.S.: m denotes slope of x+3y-3=0 while m denotes slope of the required line.

Hope that helps!