line l is the bisector of an angle a and b is any point on l.bp and bq are perpendiculars from b to the arms of angle a. show that i)angle apb congruent to angle aqb and bp=bq
Answers
Answered by
1
Step-by-step explanation:
APB=∠AQB (Each 90
o
)
∠PAB=∠QAB (l is the angle bisector of ∠A)
AB=AB (Common)
∴△APB≅△AQB (By AAS congruence rule)
∴BP=BQ (By CPCT)
It can be said that B is equidistant from the arms of ∠A.
Answered by
0
Answer:
In △APB and △AQB
∠APB=∠AQB (Each 90
o
)
∠PAB=∠QAB (l is the angle bisector of ∠A)
AB=AB (Common)
∴△APB≅△AQB (By AAS congruence rule)
∴BP=BQ (By CPCT)
It can be said that B is equidistant from the arms of ∠A
Similar questions