Question

line l is the bisector of angle A and B is any point on l. BP in BQ are perpendiculars from B to the arms of angle A .
Show that :-
i) ️APB correspondes to ️AQB
ii) BP=BQ or Pis equidistant from the arms of angle A​

Answer 1

Answer:

Given:l is the bisector of ∠A

So,∠PAB=∠QAB .......(1)

BP and BQ are perpendiculars from B,

So, ∠APB=∠AQB=90

∘

........(2)

In △APB and △AQB,

∠APB=∠AQB from (2)

∠PAB=∠QAB from (1)

AB=AB (common)

∴△APB≅△AQB by AAS congruency rule

∴BP=BQ by CPCT

Hence proved.

Answer 2

Answer:

line l is the bisector of angle A and B is any point on l. BP in BQ are perpendiculars from B to the arms of angle A .

Show that :-

i) ️APB correspondes to ️AQB

ii) BP=BQ or Pis equidistant from the arms of angle A ok