line l is the common tengent to both the circle tuching at point B and C line M is another tengent both are circle at point A then prove that angle BAC=90°,point D is the midpoint of seg BC.
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We have
Then,
O and O
′
be the centre of two circles.
XY be a common tangent.
P is the mid point of OandO
′
.
Construct:-draw OX and OX
′
.
Then,
InΔOPXandO
′
PX
OP=O
′
P(radiusofcircle)
PX=PX(Commonline)
∠XPO=∠XPO
′
(Every90
o
)
Then,
ΔOPX≅ΔO
′
PX
So, OPO
′
are collinear
.
.
. mark as brainless
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