Question

`Line L1:y-x+2=0 strikes positive X-axis at a point A and gets reflected and becomes L2=0 Line L2=0 strikes again Y-axis and after reflection from Y-axis, it becomes L3=0 . Line L3=0 meetsthe line L4:y+x-4=0 at a point B. If the equation of the line passing through A and B be y=mx+c ,then c+m= `

Answer 1

Answer:

Step-by-step explanation:

We know that, reflection of a point (x, y) in y-axis is (-x, y).

So, the point (−2,0) when reflected in y-axis is mapped to (2,0).

Hence, the mirror line is the y-axis and it's equation is x=0

Equation of incident ray =x−2y−3=0

surface =3x−2y+7=0

Answer 2

Answer:if y=mx+c means it cuts at y intercepts so if we put x=0 in x+y=4 then we get y intercepts as 4 then by solving x and y as ex (2,2) and (4,0) slope is -1 then m+c (c =y intercepts) 4-1 =3

Step-by-step explanation: