Math, asked by bsbb171, 1 year ago

Line n passes through points (6,5) and (0, 1). What is the y-intercept of line k, if line k is perpendicular to line n and passes through the point (2,4)?

Answers

Answered by KNVCSG
0

Given Line 'k' is perpendicular to line joining (6, 5) & (0, 1) and passes through (2, 4)! So!

Use

(y \:  - y1) =  \frac{x1 - x2}{y2 - y1}(x - x1)

So (y - 4) = ((6 - 0)/(1 - 5)) * (x - 2)

=>6x + 4y = 28

=>x/(14/3) + y/7 = 1

So y - intercept is 7!

Answered by 7868878894
0

Answer:

7

Step-by-step explanation:

Given Line 'k' is perpendicular to line joining (6, 5) & (0, 1) and passes through (2, 4)! So!

Use

So (y - 4) = ((6 - 0)/(1 - 5)) * (x - 2)

=>6x + 4y = 28

=>x/(14/3) + y/7 = 1

So y - intercept is 7!

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