Line PA and PB are tangents to the circle with
centre O. If ∠ = 50° ∠.
Answers
Answered by
4
ANsWeR :-
refer to the attachment
Attachments:
Answered by
11
In □PAOB,
∠APB+∠PBO+∠AOB+∠PAO=360°
....Angle sum property of quadrilateral
⇒∠AOB=360−(50°+90°+90°)=130°
So, option D is correct.
Answered By
Similar questions