line Passes through point (-√2,2) parallel to the line √2x +5y = √3
what will be the equation of line?
with explanation need answer....
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Step-by-step explanation:
√2x +5y - √3 = 0
m = - √2/5
The line parallel therefore there slopes are same = - √2/5
By slope point form=>
(y-√2 ) = m (x+√2)
5 y - 5√2 = -√2x +2
√2x+5y+2 -5√2 = 0
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