Question

line PQ is parallel to line Rs where points P Q R and S have the coordinates(2, 4), (3, 6), (3, 1) and (5, k) respectively find the value of k

Answer 1

Answer:

Step-by-step explanation:

now using slope = y2-y1 ÷ x2-x1

slope of PQ = 6-4÷3-2

                   = 2÷1 = 2

parallel lines have equal slope

slope of RS = k-1÷5-3

                2 = k-1÷2

                4 = k-1

        thus k = 4+1

                   = 5

Answer 2

K=5

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