Question

line segment AB is parallel to another line - segment CD.O is the mid point of AD show that
(1) triangle AOB=triangle DOC
(2)O is also mid - point of BC​

Answer 1

Step-by-step explanation:

given AB=CD

O is the mid point

to proof =ABC is congruent to DOC

proof = in triangle AOB and DOC ,

AB=CD (given )

<OAB = <ODC (alternate interior angle )

<AOB =<DOC (vertically opposite angle )

therefore , triangle AOB is congruent to DOC (ASA rule )

OB =OC ( c.p.c.t )

hence, o mid point of BC