Question

Line segment AB is paralleled to another line segment CD. O is the mid point of AD. Show that

triangle AOB congruent to Triangle DOC.

O is the mid point of BC.

Answer 1

Here both triangles will get congruent by ASA rule.

hint ; VOA
one side is give equal
Alt. interior angle.


Then by cpct , CO = BO i.e O is mid point of CB.
proved.




You just now try to solve .If you can't then again tell me .OK


Thanks.

Answer 2

Answer:

Given: AB = CD ; O is the mid - point .

To proof : ABC is congruent to DOC

Proof : IN triangle AOB and DOC ,

AB = CD ( given )

<OAB = <ODC ( alternate interior angles )

<AOB = <DOC ( vertically opposite angles )

Therefore , triangle AOB is congruent to DOC (ASA rule )

OB = OC ( C.PC.CT)

Hence , O is also the mid point of BC

Step-by-step explanation:

n triangle AOB & triangle DOC

Angle OAB = angle ODC [alt.int. angles]

Angle SOB =angle DOC[V.O.A]

AO=OD(given)

Triangle SOB congruent to triangle DOC(A.S.A)

OB=OC(c.p.c.t.)

Hence o is the mid point of BC