line segments ab and CD intersect at point E EA is equal to ED and EB is equal to EC prove that AC is equal to BD but that AC may not be parallel to the BD
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Step-by-step explanation:
In ∆ AEC and ∆ DEB
AE = DE (Given)
EC = EB (Given)
∠AEC = ∠DEB (Vertically opposite angle)
∴ ∆AEC ≅ ∆DEB (by S.A.S Criteria)
∴ AC = BD (by C.P.C.T)
hence, proved!
hope it helped!
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