Question

Line segments AD and BC intersect each other at point M to form two similar triangles
AMB and CMD. Given that AM = b, BM = a and CM = c, find DM in terms of a, b, c.

Answer 1

Answer:

△AMB∼△CMD [ Given ]

∴

CM

AM

=

MD

MB

[ By proportionality theorem ]

∴

z

y

=

MD

x

∴ MD=

y

xz

Answer 2

Refer To the attachment