Line segments AD and BC intersect each other at point M to form two similar triangles
AMB and CMD. Given that AM = b, BM = a and CM = c, find DM in terms of a, b, c.
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1
Answer:
△AMB∼△CMD [ Given ]
∴
CM
AM
=
MD
MB
[ By proportionality theorem ]
∴
z
y
=
MD
x
∴ MD=
y
xz
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