Question

Line segments JK and JL in the xy-coordinate plane both have a common endpoint J(-4, 11) and midpoints at M1(2, 16) and M2(-3, 5), respectively

Answer 1

Thank you for asking this question here is your answer:

distance formula : √ ((x2 - x1)^2 + (y2 - y1)^2)

(2,16)...x1 = 2 and y1 = 16

(-3,5)...x2 = -3 and y2 = 5

time to sub and solve

d = √ ((-3 - 2)^2 + (5 - 16)^2)

d = √((-5^2) + (-11^2))

d = √ (25 + 121)

d = √ 146

d = 12.08