Math, asked by abdulkhadarar93, 12 hours ago

line through the points (-3,6) (4,12) is perpendicular to the line through the points (8,15) (x,24).find the value of x​

Answers

Answered by ayushkumar1983
0

Answer:

7by \gamma  \cot(54 + 24y) ? \times \frac{?}{?}  ans = 780

ans =780

Step-by-step explanation:

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Answered by Mathematically
0

Step-by-step explanation:

Let the slope of the line through the points (-3,6) & (4,12) be m₁

And the slope of the line through the points (8,15) & (x,24) be m₂

∵ slope = Δy / Δx = (Y₂ - Y₁) / (X₂ - X₁)

∴ m₁ = (12 - 6) / (4 - (-3)) = 6 / 7

∴ m₂ = (24 - 15) / (x-8) = 9 / x - 8

Two lines are perpendicular to one another if and only if the product of their slopes is equal to negative 1 i.e. m₁ × m₂ = -1

m₁ × m₂ = (6 × 9) / 7 (x-8) = -1

54 = -1 { 7x - 56}

54 = -7x + 56

7x = 56 - 54 = 2

x = 2/7

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