line through the points (-3,6) (4,12) is perpendicular to the line through the points (8,15) (x,24).find the value of x
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Answer:
ans =780
Step-by-step explanation:
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Step-by-step explanation:
Let the slope of the line through the points (-3,6) & (4,12) be m₁
And the slope of the line through the points (8,15) & (x,24) be m₂
∵ slope = Δy / Δx = (Y₂ - Y₁) / (X₂ - X₁)
∴ m₁ = (12 - 6) / (4 - (-3)) = 6 / 7
∴ m₂ = (24 - 15) / (x-8) = 9 / x - 8
Two lines are perpendicular to one another if and only if the product of their slopes is equal to negative 1 i.e. m₁ × m₂ = -1
m₁ × m₂ = (6 × 9) / 7 (x-8) = -1
54 = -1 { 7x - 56}
54 = -7x + 56
7x = 56 - 54 = 2
x = 2/7
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