Line v passes through point (6, 6) and is perpendicular to the graph of y = 34x − 11. Line w is parallel to line v and passes through point (−6, 10). What is the equation in slope-intercept form of line w?
Answers
Answer:
y = -1/34 . x + 167/17
Step-by-step explanation:
From the above question,
They have given :
Line v passes through point (6, 6) and is perpendicular to the graph of
y = 34x − 11.
Line w is parallel to line v and passes through point (−6, 10).
The slope-intercept form of a linear equation is:
y = m.x + b
where,
m is the slope
b is the y-intercept
Line v is perpendicular to the graph of y = 34 x - 11. If two lines are perpendicular, the slope of one is the inverse and opposite of the other. Therefore, the slope of v is -1/34.
Line w is parallel to line v. When two lines are parallel, they have the same slope. Therefore, the slope of w is also -1/34.
The equation of w is:
y = -1/34 . x + b
Lines b passes through the point (-6, 10). We can replace this ordered pair in the previous equation to find the value of b.
10 = -1/34 . (-6) + b
b = 167/17
The equation of w is:
y = -1/34 . x + 167/17
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