Math, asked by khushibhadala16, 3 months ago

line Y=mx +c passes through the point a(4,6) b(8,3) determine m and c​

Answers

Answered by rayavarapunidhi
0

Answer:

m=-3/4

c=34

Step-by-step explanation:

m=y2-y1/ x2-x1

= 3-6/8-4

=-3/4

x-x1=(M) y-y1

x-4= (-3/4) y-6

4x-16=-3y +18

3y=-4x+34

Answered by vamsilanka
0

Answer:

Slope, m=(y2-y1) /(x2-x1)

m=(3-6) /(8-4) = -3/4

Equation of line=>y-y1 =m(x-x1)

=>y-6 =(-3/4) (x-4)

=>y-6 =-3/4(x) +12

=>y =(-3/4) x+18

comparing above equation with y=mx+c

m=-3/4

c=18

Similar questions