Linear combination of 32 and 56
Answers
Answered by
0
We need to find H.C.F. of 32 and 54.
By applying division lemma 54 = 32 x 1 + 22
Since remainder ≠ 0, apply division lemma on 32 and remainder 22
32 = 22 x 1 + 10
Since remainder ≠ 0, apply division lemma on 22 and remainder 10
22 = 10 x 2 + 2
Since remainder ≠ 0, apply division lemma on 10 and 2
10 = 2 x 5 + 0
Therefore, H.C.F. of 32 and 54 is
By applying division lemma 54 = 32 x 1 + 22
Since remainder ≠ 0, apply division lemma on 32 and remainder 22
32 = 22 x 1 + 10
Since remainder ≠ 0, apply division lemma on 22 and remainder 10
22 = 10 x 2 + 2
Since remainder ≠ 0, apply division lemma on 10 and 2
10 = 2 x 5 + 0
Therefore, H.C.F. of 32 and 54 is
Similar questions