linear equation 2y-3/5+y+3/4=4y+1/7
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Answers
Answer:
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Step-by-step explanation:
How to solve your question
Your question is
2
−
1
⋅
3
5
+
+
3
4
=
4
+
1
7
2y-1 \cdot \frac{3}{5}+y+\frac{3}{4}=4y+\frac{1}{7}
2y−1⋅53+y+43=4y+71
Solve
1
Multiply the numbers
2
−
1
⋅
3
5
+
+
3
4
=
4
+
1
7
2y{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{3}{5}}}+y+\frac{3}{4}=4y+\frac{1}{7}
2y−1⋅53+y+43=4y+71
2
−
3
5
+
+
3
4
=
4
+
1
7
2y{\color{#c92786}{-\frac{3}{5}}}+y+\frac{3}{4}=4y+\frac{1}{7}
2y−53+y+43=4y+71
2
Add the numbers
3
Combine like terms
4
Subtract
3
2
0
\frac{3}{20}
203
from both sides of the equation
5
Simplify
6
Subtract
4
4y
4y
from both sides of the equation
7
Simplify
8
Divide both sides of the equation by the same term
9
Simplify
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Solution
=
1
1
4
0
y=\frac{1}{140}
y=1401
Answer:
I know this answer is 29.