Question

Linear equation 3x+4y=16 intersect y axis at a point

Answer 1

Answer:

(0,4)

Solution:

Here ,

The given linear equation is ;

3x + 4y = 16 .

We need to find its point of Intersection on the y-axis .

Now,

We know that , at y-axis the x-coordinate is zero .

Thus,

Putting x = 0 in the given linear equation ,

We have ;

=> 3x + 4y = 16

=> 3•0 + 4y = 16

=> 0 + 4y = 16

=> 4y = 16

=> y = 16/4

=> y = 4

Hence ,

The line will intersect the y-axis at the point (0,4) .