Question

Linear equation by elimination method -x+5y=1and -3x+y=6

Answer 1

Answer:

This is the answer of your questions

Answer 2

$-x+5y =1 ~~~...(i)\\y-3x =6~~~...(ii)$

Multiply equation (ii) by 5 and do (ii)-(i)

$(5y-15x) +x-5y = 30-1\\\\\implies -14x = 29\\\\\implies x =-\dfrac{29}{14}$

Substitute the value of x in eq (i):

$\dfrac{29}{14} + 5y = 1\\\\\implies 5y = 1 -\dfrac{29}{14} =- \dfrac{15}{14}\\\\\implies y =- \dfrac{15}{70}=-\dfrac{3}{14}$

Hence

$(x,y) = \left(-\dfrac{29}{14} , -\dfrac{3}{14} \right)$