Linear equation for : 5 subtracted from twice a number is 7
A - 2x - 7 =5
B= 2x - 5=7
C- x=6
D - 5 - 2 x = 7
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Answer:
(i) Let the required number be x.
So, five times the number will be 5x.
∴ 5x = 40
(ii) Let the required number be x.
So, when it is increased by 8, we get x + 8.
∴ x + 8 = 15
(iii) Let the required number be x.
So, when 25 exceeds the number, we get 25 - x.
∴ 25 - x = 7
(iv) Let the required number be x.
So, when the number exceeds 5, we get x - 5.
∴ x - 5 = 3
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