Question

Linear equation in one variable

Answer 1

$( \frac{3x + 1}{16}) + ( \frac{2x - 3}{7} ) = (\frac{x + 3}{8} ) + ( \frac{3x - 1}{14} )$
$( \frac{3x + 1}{16} ) - ( \frac{x + 3}{8}) = ( \frac{3x - 1}{14} ) - ( \frac{2x - 3}{7} ) \\ ( \frac{3x + 1 - 2x - 6}{16} ) = ( \frac{3x - 1 - 4x + 6}{14} ) \\ ( \frac{x - 5}{16} ) = ( \frac{ - x + 5}{14} ) \\ cross \: multiply \\ 14(x - 5) = 16(5 - x) \\ 14x - 70 = 80 - 16x \\ 14x + 16x = 80 + 70 \\ 30x = 150 \\ x = \frac{150}{30} \\ x = 5$

Answer 2

Answer:

=>(3x + 1)/16 +(2x-3)/7 = (x+3)/8+ (3x-1)/14

=> (3x+1)/16 - (x+3)/8 = (3x-1)/14 - (2x-3)/7

=> (3x+1) - 2(x+3)/16 = (3x-1) -2(2x-3) /14

=> 3x+1-2x-6/16= 3x-1-4x+6/14

=>x- 5/16 = -x +5/14

Now cross multiplication,

=> -16x +80= 14 x -70

=> 80+ 70 = 14 x + 16x

=> 150 = 30x

=> x = 150/30

=> x = 5

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