Question

linear equation math question​

Answer 1

Answer:

x=1

Step-by-step explanation:

$\frac{3}{x+2}-\frac{1}{x+1}=\frac{2}{x+3}$

$\frac{3}{x+2}+\frac{-1}{x+1}=\frac{2}{x+3}$

Multiply all terms by (x+2)(x+1)(x+3) and cancel:

$3(x+1)(x+3)+-1(x+2)(x+3)=2(x+2)(x+1)$

$2x^2+7x+3=2x^2+6x+4$ (Simplify both sides of the equation)

$2x^2+7x+3-2x^2=2x^2+6x+4-2x^2$ (Subtract 2x^2 from both sides)

$7x+3=6x+4$

$7x+3-6x=6x+4-6x$ (Subtract 6x from both sides)

$x+3=4$

$x+3-3=4-3$ (Subtract 3 from both sides)

$x=1$