Math, asked by reemarakshit500, 9 months ago

linear
equation
solve the following part al
the Cross multipliation method
x- 3y-7= 0
3x-3y-15=0​

Answers

Answered by janardhan9098
2

Step-by-step explanation:

x-3y=7_____1

3x-3y=15______2

subtracting both the equation

x-3y=7

- 3x-3y=15

(-) (+) (-)

____________

-2x = 8

x=8/-2

x= -4

substituting x=-4 to equation 1

x-3y=7

-4-3y=7

-4-7=3y

-11=3y

y=-11/3

solution of x=-4

solution of y=-11/3

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