Linear equation : the sum of three consecutive multiples of 3 is 333. Find the multiples
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1st: 3x
2nd: 3x+3 = 3(x+1)
3rd: 3x+6 = 3(x+2)
Now the Equation becomes
3(x+x+1+x+2) = 333
3x+3 = 111
3x = 108
x = 36
3x = 108
3(x+1) = 111
3(x+2) = 114
2nd: 3x+3 = 3(x+1)
3rd: 3x+6 = 3(x+2)
Now the Equation becomes
3(x+x+1+x+2) = 333
3x+3 = 111
3x = 108
x = 36
3x = 108
3(x+1) = 111
3(x+2) = 114
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