linear equation through substitution method 5x+4y=4,x-20=12y
Answers
Answer:
Value of x is 2 and y is -3/2 .
Step-by-step explanation:
We have ,
• 5x + 4y = 4
• x - 20 = 12y
Let, equations be
• 5x + 4y = 4 ------(i)
• x - 20 = 12y -------(ii)
Take equation (ii) :
→ x - 20 = 12y
→ x = 12y + 20 ------(iii)
Put equation (iii) in equation (i) :
→ 5x + 4y = 4 ----(i)
→ 5 × (12y + 20) + 4y = 4
→ 60y + 100 + 4y = 4
→ 64y + 100 = 4
→ 64y = 4 - 100
→ 64y = -96
→ y = -96/64
→ y = -3/2
Now, Put value of y in any equation :
→ x = 12y + 20 ----(iii)
→ x = 12 × (-3/2) + 20
→ x = -36/2 + 20
→ x = (-36 + 40)/2
→ x = 4/2
→ x = 2
Thus,
Value of x is 2 and y is -3/2 .
QUESTION:-
SOLVE EQUATION USING SUBSTITUTION METHOD
5x+4y=4,x-20=12y
EXPLANATION:-
Let,
5x+4y=4---eq-1
x-20=12y----eq-2
Solve for x in eq-2
x-20=12y
x=12y+20
Substitute x=12y+10 in eq-1
5(12 5 × (12y + 20) + 4y = 4
=> 60y + 100 + 4y = 4
=> 64y + 100 = 4
=> 64y = 4 - 100
=> 64y = -96
=>y = -96/64
=>y = -3/2
Put y=-3/2 in eq-1
5×x+4(-3/2)=4
x=-36/2+20
x=(-36+40)/2
x=2
So,
x=2 and y=-3/2
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