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Q1 . man is twice as old as his son. 20 years ago the age of the man was twelve times the age of the son . find their present ages.

Answer 1

$\rm{Let \: sons \: age \:be \: x.}$

$\rm{Then, fathers \: age = 2x.}$

$\sf \green{12(x—2O) = (2x - 20) } \\ \sf \purple{x = 22}$

$\fcolorbox{purple}{pink}{Fathers present age = 44 years}$

Answer 2

Answer:

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