Linear Equations in One Variable
25. A man is 4 times as old as his son. After 16 years he will be only twice as old as his son.
Find their present ages.
Answers
Answered by
1
Answer:
father' s age is 32
son ' s age is 8
Step-by-step explanation:
let the ade of son be X and father age be 4X
Age after 16 years , fathers age 4X + 16
Age after 16 years , son age X + 16
ATQ,
4X+16 = 2(X + 16)
4X+16 = 2X + 32
4X - 2X = 32 - 16
2X = 16
X = 8
fathers age = 32
son age = 8
Answered by
5
Hope it's help you
Have a nice day..
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