Math, asked by yadavvansh92677, 2 months ago

Linear Equations in One Variable
25. A man is 4 times as old as his son. After 16 years he will be only twice as old as his son.
Find their present ages.​

Answers

Answered by raunak180439
1

Answer:

father' s age is 32

son ' s age is 8

Step-by-step explanation:

let the ade of son be X and father age be 4X

Age after 16 years , fathers age 4X + 16

Age after 16 years , son age X + 16

ATQ,

4X+16 = 2(X + 16)

4X+16 = 2X + 32

4X - 2X = 32 - 16

2X = 16

X = 8

fathers age = 32

son age = 8

Answered by pari9054
5

Hope it's help you

Have a nice day..

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