Question

Linear Equations in One Variable Ex 9.3 Q14 ​

Answer 1

Answer:

Q14 (x+1x+2)2 = x+2x+4

Sol:

(x+1x+2)2 = x+2x+4

=> x2+2x+1x2+4x+4 = x+2x+4

=> x3+2x2+x+4x2+8x+4=x3+4x2+4x+2x2+8x+8

=> x3–x3+6x2–6x2+9x–12x=8–4

=> -3x = 4

=>     x = −43

Verification

L.H.S = (−43+1−43+2)2

= (−4+3−4+6)2

= 14

R.H.S = −43+1−43+2

= −4+6−4+12

= 28

= 14

Hence, L.H.S = R.H.S