Question

linear equations in one variable.......i have exams tomorrow
help me guys../mates..
ans. is given on the RHS...

Answer 1

the answer is in the picture thanks for asking

Answer 2

SOLUTION :

$= \frac{3}{5} (3x + 1) - \frac{2x}{3} = \frac{4}{5} + (2x - \frac{x + 1}{3} \\ = \frac{9x}{5} + \frac{3}{5} - \frac{2x}{3} = \frac{4}{5} + \frac{6x}{3} - \frac{x + 1}{3} \\ = \frac{9x + 3}{5} - \frac{2x}{3} = \frac{4}{5} + \frac{6x - x + 1}{3} \\ = \frac{9x + 3}{5} - \frac{2x}{3} = \frac{4}{5} + \frac{5x + 1}{3} \\ = \frac{9x + 3}{5} - \frac{4}{5} = \frac{5x + 1}{3} + \frac{2x}{3} \\ = \frac{9x + 3 - 4}{5} = \frac{5x + 1 + 2x}{3} \\ = \frac{9x - 1}{5} = \frac{7x + 1}{3} \\ = cross \: multiply \\ = 3(9x - 1) = 5(7x + 1) \\ = 27x - 3 = 35x + 5 \\ = - 3 - 5 = 35x - 27x \\ = - 8 = 8x \\ = \frac{ - 8}{8} = x \\ = - 1 = x$

HOPE IT HELPS YOU

PLZ MARK ME BRAINLIEST