Question

linear equations math question class 8​

Answer 1

Answer:

Hey There!

$\frac{3}{x + 1} - \frac{2}{x - 1} = \frac{5}{ {x}^{2} - 1 }$

Now we need to multiply by lcm

So we need to find the least common multiplier of x+1,x-1,x^2-1

So factor

${x}^{2} - 1$

Apply the Difference of two square formula

${x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} - {1}^{2} = (x + 1)(x - 1) \\ = (x + 1)(x - 1)$

x-5=5

Multiply x-5+5=5+5

x=10

So x=10 is the answer

$\Large\textsf{Hope \: It \: Helped}$

Answer 2

Answer:

x= 10

Step-by-step explanation:

Variable x cannot be equal to any of the values −1,1 since division by zero is not defined. Multiply both sides of the equation by (x−1)(x+1), the least common multiple of x+1,x−1,x

2

−1.

(x−1)×3−(x+1)×2=5

Use the distributive property to multiply x−1 by 3.

3x−3−(x+1)×2=5

Use the distributive property to multiply x+1 by 2.

3x−3−(2x+2)=5

To find the opposite of 2x+2, find the opposite of each term.

3x−3−2x−2=5

Combine 3x and −2x to get x.

x−3−2=5

Subtract 2 from −3 to get −5.

x−5=5

Add 5 to both sides.

x=5+5

Add 5 and 5 to get 10.

x=10