Question

linear momentum of a particle of mass m is p, the K.E. is- (a) mp (b) 2p^2/m (c) p^2/m (d) p^2/2m​

Answer 1

Explanation:

KE = $\dfrac{1}{2}mv²$

now we know that,

linear momentum (p) = mass × velocity

》p= mv

》p² = m²v²

》$\dfrac{p²}{2m}$ =$\dfrac{m²v²}{2m}$

》$\dfrac{p²}{2m}$ =$\dfrac{1}{2}mv²$

》kinetic energy = $\dfrac{p²}{2m}$

d) option is correct.