Question

linear width of secondary maxima​

Answer 1

Answer:(2λD)/a

Explanation:tanθ=y/D

For small angle θ, tanθ=θ

So, θ=y/D

=> λ/a=y/D

=> y=λD/a (linear width of minima)

Linear width of central maxima = 2y

So, 2y=2λD/a