Question

liner equations in one varible linear equations in one varible 3y+2/3=2y+1

Answer 1

Question:-

Solve the equation 3y + 2/3= 2y + 1

Solution:-

$\to \bf \: 3y + \frac{2}{3} = 2y + 1$

By taking LCM , we get

$\to \bf \: \frac{9y + 2}{3} = 2y + 1$

By using cross multiplication

$\bf \to \: 9y + 2 = 3(2y + 1)$

$\to \bf \: 9y + 2 = 6y + 3$

$\to \bf \: 9y - 6y = 3 - 2$

$\to \bf \: 3y = 1$

$\to \bf \: y = \frac{1}{3}$

$\bf \: value \: \: of \: \: y = \frac{1}{3}$

Answer 2

Answer:

-1/2 = y

Step-by-step explanation:

here, we need to bring all the numerical values to one side and all the variables to one side. so, we transpose.

• 3y + 2/3 = 2y + 1

• 3y = 2y + 1 - 3/2 (if we take 2/3 to the other side, it will become the reciprocal of itself and its sign will be changed.)
• 3y - 2y = 1 - 3/2 (if we take 2y to the to the other side, the sign will change from + to - )
• y = 1 - 3/2 (we subtract 2y from 3y to give 1y.)
• y = 1/1 - 3/2
• y = 2/2 - 3/2 (we make the denominators of the fractions on the RHS equal so that we can subtract them.)
• y = -1/2

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