Question

Lines a and b are cut by transversal f. At the intersection of lines f and a, the top left angle is 96 degrees. At the intersection of lines b and f, the bottom right angle is (6 x minus 36) degrees.
What must be the value of x so that lines a and b are parallel lines cut by transversal f?

Answer 1

Answer:

for a and b to be parallel lines

sum of co exterior angle= 180

96+(6x-36)=180

6x+60=180

x= (180-60)/6=120/6=20

Step-by-step explanation:

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