Lines AB and CD intersect at O. If ∟AOC=(3x-10o) and ∟BOD=(20o-2x), then the value of x is
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Given :-
- Lines AB and CD intersect at O.
- ∠AOC = (3x - 100°)
- ∠BOD = (200° - 2x)
To find :-
- value of x ?
Solution :-
we know that, when two lines cross, the angles at intersection point opposite to each other are equal by vertically opposite angles.
Given that, Lines AB and CD intersect at O.
So,
→ ∠AOC = ∠BOD ( vertically opposite angles. )
Putting values we get,
→ (3x - 100°) = (200° - 2x)
→ 3x + 2x = 200 + 100
→ 5x = 300
Dividing both sides by 5,
→ x = 60° . (Ans.)
Hence, value of x is 60° .
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