lines AB and CD intersect at point O . if angle AOD : angle BOD = 4:5 . find all the angle
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Answered by
54
If <AOD: <BOD = 4:5,
Let <AOD and <BOD be 4x and 5x
4x+5x=180 (linear pair)
9x=180°
x=180÷9
x=20
So, <AOD = 4x = 4×20 =80°
<BOD = 5x = 5×20 =100°
To find <COB,
<COB+<DOB=180° (linear pair)
<COB+100=180°
<COB=180-100
<COB=80°
To find <AOC,
<AOC+<COB=180° (linear pair)
<AOC+80=180°
<AOC=180-80
<AOC=100°
Answered by
7
Answer:
answer is equal to angle AOC is equal to 55 degree angle C is equal to 105 degree angle is equal to 105 degree angle b o f is equal to 20 degree
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